Bearing Knowledge Encyclopedia (7)

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Bearing Knowledge Encyclopedia (7)

Source: China Bearing Network Time: 2017-10-03

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Operating cycle and bearing load. The analysis of the gear force and the operating cycle of the transmission indicate that the bearing receives a radial load of 1780 N for approximately 3/4 of the time; the rotational speed is 11000 r/min; The bearing receives a radial load of 890 N; the rotational speed is 3500 r/min. The outstanding positive meshing hardly produces axial force; there is no oblique meshing or other useful axial component. The maximum axial force in both directions is estimated. 89N; the maximum oscillation force is 89N.
Scale limit. Because of the constraints depicted inside the reducer; the maximum outer diameter of the bearing is 70mm; the maximum accounting disturbance is 6; the maximum azimuth is 0,0015. The aligning bearing is not required.
Environment. The smoothness of the bearing is the same as the smoothness of the mesh: from a large oil tank; the maximum temperature is 140 F.
Reliability. Bearings must have a good reliability for continuous operation; use 8% of reliable power loss.
Picking process 1. The inner diameter of the bearing is about 25mm.
2. The outer diameter of the bearing is 70mm.
3. Estimate the maximum pitch diameter D (the average of the inner and outer diameters of the bearing) as:
(25+70)/2=47.5(mm)
4. Calculate the maximum DN value:
47. 5 × 11000 = 0, 52 × 106
5. In order to select the type of essential bearing required; determine the DN value of the correction. First; find out the limit speed coefficient of the modified bearing from the smooth type. Obtained from Figure 12; when the small oil tank is used in succession, the coefficient is 0. 85. When using large oil tank intermittent operation; the coefficient is 0, 95; take the low coefficient value in the continuous operation; the DN value of the correction is:
1. 52×10? ) /0, 85=0, 61×106
1. Using the DN value obtained in Process 5 and the results of Figure 12; we found that the angular speed (limit speed) of angular touch ball bearings and industrial grade, precision cylindrical roller bearings, and deep groove ball bearings is equal to or greater than the corrected DN value. ; thus; these are the types of bearings that are selected.
2. Calculate the equivalent load from equation (D):
3. Determine the basic life of the reducer. Obtained from Expression 1 4; the typical operating life of the general reducer is 20000h.
4. The lifespan of the operation is corrected with a given reliability loss. The life correction coefficient given by the expression 1 5; 8% of the reliability loss is 85%, so the lifespan L of the correction operation is:
20000/0.85=23529(h)
10. Calculate the additional dynamic load C of the demand using equation (E):
11. Use oscillation to correct C. In this example, the minimum stability load 890N is greater than the maximum oscillation load of 89N; the ratio of the oscillating load to the stability load is 0.1; using Table 16. The linear interpolation method is used to puncture a batch between the two closest load rates. Coefficient value; the coefficient is calculated as follows:
(1.00+1.020)/2=1.010
Then the batch value of the additional load is:
C=1.010×29746(N)
12. Different axial degrees according to different axial degrees and azimuths of deflection; determine whether it is necessary to correct C.
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